Can't you think like this---perhaps it is too much of a physicist's
thinking. We can think of the following general function (operator
in physics) that produces an image y of x operated upon by A.
y = Ax
if x is from the domain of positive integers, then A = -1 would
produce an image that is opposite to the one when A = +1, the
identity operation.
Conceptually you would then not think in terms of a positive times
a negative number, but in terms of a positive number that is
projected opposite of the origin on a number line, and, if the
number is unequal to 1, like -2, then it is also stretched.
The - would then not be interpreted in the same way as the +
Cheers,
Michael
On 27-Apr-09, at 4:16 PM, Ed Wall wrote:
Mike
It is simply (of course, it isn't simple by the way) because,
the negative integers (and, if you wish, zero) were added to the
natural numbers in a way that preserves (in a sense) their (the
natural numbers) usual arithmetical regularities. It would be
unfortunate if something that was true in the natural numbers was
no longer true in the integers, which is a extension that includes
them. Perhaps the easiest way to the negative x positive business
is as follows (and, of course, this can be made opaquely precise -
smile):
3 x 1 = 3
2 x 1 = 2
1 x 1 = 1
0 x 1 = 0
so what, given regularity in the naturals + zero) do you think
happens next? This thinking works for, of course, for negative
times negative. The opaque proof is more or less as follows.
Negative numbers are solutions to natural number equations of the
form (I'm simplifying all this a little)
x + a = 0 ('a' a natural number)
and likewise positive numbers are solutions to natural number
equations of the form
y = b ('b' a natural number)
Multiplying these two equations in the usual fashion within the
natural numbers gives
xy + ay = 0
or substituting for y
xy + ab = 0
so, by definition, xy is a negative number.
Notice how all this hinges on the structure of the natural numbers
(which I've somewhat assumed in all this).
Ed
On Apr 27, 2009, at 6:47 PM, Mike Cole wrote:
Since we have some mathematically literate folks on xmca, could
someone
please post an explanation of why
multiplying a negative number by a positive numbers yields a negative
number? What I would really love is an explanation
that is representable in a manner understandable to old college
professors
and young high school students alike.
mike
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